WebMar 28, 2024 · Transcript. Ex 6.2, 6 In figure, A, B and C are points on OP, OQ and OR respectively such that AB PQ and AC PR. Show that BC QR. Given: AB II PQ and AC II PR To prove: BC II QR Proof: In ∆ 𝑂𝑃𝑄 AB II PQ (Line drawn parallel to one side of triangle, intersects the other two sides in distinct points, Then it divides the other 2 ... WebMar 5, 2024 · In the given figure if DE ∥BC, AD = 2.5 cm, DB = 3.5 cm and EC = 4.2 cm, then the measure of AC is: This question was previously asked in SSC CGL Previous Paper 73 (Held On: 5 March 2024 Shift 3) Attempt Online View all SSC CGL Papers > 3 cm 3.2 cm 7.2 cm 7.4 cm Answer (Detailed Solution Below) Option 3 : 7.2 cm Free Tests View all Free …
In ΔABC,DE ll BC,find the value of x. - Sarthaks
WebBC = 2(5) + 2 = 10 + 2 = 12. AC = 3x = 3(5) = 15. DF = 6(5) = 30. EF = 3(5) + 9 = 15 + 9 = 24. Therefore, the length of the sides of the triangle are AB = 9 cm, BC = 12 cm, AC = 15 cm, DE = 18 cm, EF = 24 cm and DF = 30 cm. Try This: Let ABC and DEF be two triangles in which AB = DE, BC = FD and CA = EF. The two triangles are congruent under ... WebMar 27, 2024 · Complete step by step solution: In the given triangle ABC. We are given that AC = BC. This means that it is an isosceles triangle. And in an isosceles triangle the … skechers christmas shoes
In the given figure, if DE BC, then find the length of AC
WebIn given figure, ABC is a triangle right angled at B and BD⊥AC. If AD =4 cm and CD = 5cm, then find BD and AB. Solution Given, ΔABC in which ∠B= 90∘ and BD⊥ AC. Also, AD = 4cm and CD = 5cm In ΔADB and ΔCDB, ∠ADB=∠CDB [each equal to 90∘] ∠BAD=∠DBC [each equal to 90∘ −∠C ] ∴ ΔDBA∼ΔDCB [by AAA similarity criterion] Then, DB DA = DC DB ⇒ DB2 … Web∴ DE BC (Two lines are parallel if the corresponding angles formed are equal) According to basic proportionality theorem if a line is parallel to one side of a triangle intersecting the other two sides, then it divides the two sides in the same ratio. In ∆ABC, DE BC A D D B = A E E C 2 3 = 3 E C E C = 3 × 3 2 E C = 9 2 Web(a) In the figure given below, AB DE, AC = 3 cm, CE = 7.5 cm and BD = 14 cm. Calculate CB and DC. Solution:- From the question it is given that, AB DE AC = 3 cm CE = 7.5 cm BD = 14 cm From the figure, ∠ACB = ∠DCE [because vertically opposite angles] ∠BAC = ∠CED [alternate angles] Then, ∆ABC ~ ∆CDE So, AC/CE = BC/CD 3/7.5 = BC/CD skechers chunky shoes